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Using sum and difference formulas for cofunctions

Now that we can find the sine, cosine, and tangent functions for the sums and differences of angles, we can use them to do the same for their cofunctions. You may recall from Right Triangle Trigonometry that, if the sum of two positive angles is π 2 , those two angles are complements, and the sum of the two acute angles in a right triangle is π 2 , so they are also complements. In [link] , notice that if one of the acute angles is labeled as θ , then the other acute angle must be labeled ( π 2 θ ) .

Notice also that sin θ = cos ( π 2 θ ) , which is opposite over hypotenuse. Thus, when two angles are complimentary, we can say that the sine of θ equals the cofunction of the complement of θ . Similarly, tangent and cotangent are cofunctions, and secant and cosecant are cofunctions.

Image of a right triangle. The remaining angles are labeled theta and pi/2 - theta.

From these relationships, the cofunction identities are formed. Recall that you first encountered these identities in The Unit Circle: Sine and Cosine Functions .

Cofunction identities

The cofunction identities are summarized in [link] .

sin θ = cos ( π 2 θ ) cos θ = sin ( π 2 θ )
tan θ = cot ( π 2 θ ) cot θ = tan ( π 2 θ )
sec θ = csc ( π 2 θ ) csc θ = sec ( π 2 θ )

Notice that the formulas in the table may also justified algebraically using the sum and difference formulas. For example, using

cos ( α β ) = cos α cos β + sin α sin β ,

we can write

cos ( π 2 θ ) = cos π 2 cos θ + sin π 2 sin θ = ( 0 ) cos θ + ( 1 ) sin θ = sin θ

Finding a cofunction with the same value as the given expression

Write tan π 9 in terms of its cofunction.

The cofunction of tan θ = cot ( π 2 θ ) . Thus,

tan ( π 9 ) = cot ( π 2 π 9 ) = cot ( 9 π 18 2 π 18 ) = cot ( 7 π 18 )
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Write sin π 7 in terms of its cofunction.

cos ( 5 π 14 )

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Using the sum and difference formulas to verify identities

Verifying an identity means demonstrating that the equation holds for all values of the variable. It helps to be very familiar with the identities or to have a list of them accessible while working the problems. Reviewing the general rules presented earlier may help simplify the process of verifying an identity.

Given an identity, verify using sum and difference formulas.

  1. Begin with the expression on the side of the equal sign that appears most complex. Rewrite that expression until it matches the other side of the equal sign. Occasionally, we might have to alter both sides, but working on only one side is the most efficient.
  2. Look for opportunities to use the sum and difference formulas.
  3. Rewrite sums or differences of quotients as single quotients.
  4. If the process becomes cumbersome, rewrite the expression in terms of sines and cosines.

Verifying an identity involving sine

Verify the identity sin ( α + β ) + sin ( α β ) = 2 sin α cos β .

We see that the left side of the equation includes the sines of the sum and the difference of angles.

sin ( α + β ) = sin α cos β + cos α sin β sin ( α β ) = sin α cos β cos α sin β

We can rewrite each using the sum and difference formulas.

sin ( α + β ) + sin ( α β ) = sin α cos β + cos α sin β + sin α cos β cos α sin β = 2 sin α cos β

We see that the identity is verified.

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Verifying an identity involving tangent

Verify the following identity.

sin ( α β ) cos α cos β = tan α tan β

We can begin by rewriting the numerator on the left side of the equation.

sin ( α β ) cos α cos β = sin α cos β cos α sin β cos α cos β = sin α cos β cos α cos β cos α sin β cos α cos β Rewrite using a common denominator . = sin α cos α sin β cos β Cancel . = tan α tan β Rewrite in terms of tangent .

We see that the identity is verified. In many cases, verifying tangent identities can successfully be accomplished by writing the tangent in terms of sine and cosine.

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Questions & Answers

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If auger is pair are the roots of equation x2+5x-3=0
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Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
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Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
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Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
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-42m²+60m-18
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-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
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A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
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The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
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Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
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Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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