9.5 Solving trigonometric equations  (Page 7/10)

$2\sin \theta =\mathrm{-}\sqrt{2}$

$2\sin \theta =\sqrt{3}$

$2\cos \theta =1$

$2\cos \theta =\mathrm{-}\sqrt{2}$

$\tan \theta =\mathrm{-1}$

$\tan x=1$

$\cot x+1=0$

$4{\sin }^{2}x-2=0$

${\csc }^{2}x-4=0$

$2\cos \theta =\sqrt{2}$

$2\cos \theta =\mathrm{-1}$

$2\sin \theta =\mathrm{-1}$

$2\sin \theta =\mathrm{-}\sqrt{3}$

$2\sin \left(3\theta \right)=1$

$2\sin \left(2\theta \right)=\sqrt{3}$

$2\cos \left(3\theta \right)=-\sqrt{2}$

$\cos \left(2\theta \right)=-\frac{\sqrt{3}}{2}$

$2\sin \left(\pi \theta \right)=1$

$2\cos \left(\frac{\pi }{5}\theta \right)=\sqrt{3}$

$\sec (x)\sin (x)-2\sin (x)=0$

$\tan (x)-2\sin (x)\tan (x)=0$

$2{\cos }^{2}t+\cos \left(t\right)=1$

$2{\tan }^2(t)=3\sec (t)$

$2\sin (x)\cos (x)-\sin (x)+2\cos (x)-1=0$

${\cos }^2\theta =\frac{1}{2}$

${\sec }^{2}x=1$

${\tan }^2\left(x\right)=\mathrm{-1}+2\tan \left(-x\right)$

$8{\sin }^2(x)+6\sin (x)+1=0$

${\tan }^5(x)=\tan (x)$

$\sin (3x)\cos (6x)-\cos (3x)\sin (6x)=\mathrm{-0.9}$

$\sin (6x)\cos (11x)-\cos (6x)\sin (11x)=\mathrm{-0.1}$

$\cos \left(2x\right)\cos x+\sin \left(2x\right)\sin x=1$

$6\sin \left(2t\right)+9\sin t=0$

$9\cos \left(2\theta \right)=9{\cos }^2\theta -4$

$\sin \left(2t\right)=\cos t$

$\cos \left(2t\right)=\sin t$

$\cos (6x)-\cos (3x)=0$

${\tan }^{2}x-\sqrt{3}\tan x=0$

${\sin }^{2}x+\sin x-2=0$

${\sin }^{2}x-2\sin x-4=0$

$5{\cos }^{2}x+3\cos x-1=0$

$3{\cos }^{2}x-2\cos x-2=0$

$5{\sin }^{2}x+2\sin x-1=0$

${\tan }^{2}x+5\tan x-1=0$

${\cot }^{2}x=-\cot x$

$-{\tan }^{2}x-\tan x-2=0$

${\sin }^{2}x-{\cos }^{2}x-\sin x=0$

${\sin }^{2}x+{\cos }^{2}x=0$

$\sin \left(2x\right)-\sin x=0$

$\cos \left(2x\right)-\cos x=0$

$\frac{2\tan x}{2-{\sec }^{2}x}-{\sin }^{2}x={\cos }^{2}x$

$1-\cos (2x)=1+\cos (2x)$

${\sec }^{2}x=7$

$10\sin x\cos x=6\cos x$

$\mathrm{-3}\sin t=15\cos t\sin t$

$4{\cos }^{2}x-4=15\cos x$

$8{\sin }^{2}x+6\sin x+1=0$

$8{\cos }^2\theta =3-2\cos \theta$

$6{\cos }^{2}x+7\sin x-8=0$

$12{\sin }^{2}t+\cos t-6=0$

$\tan x=3\sin x$

${\cos }^{3}t=\cos t$

$6{\sin }^{2}x-5\sin x+1=0$

$8{\cos }^{2}x-2\cos x-1=0$

$100{\tan }^{2}x+20\tan x-3=0$

$2{\cos }^{2}x-\cos x+15=0$

$20{\sin }^{2}x-27\sin x+7=0$

$2{\tan }^{2}x+7\tan x+6=0$

$130{\tan }^{2}x+69\tan x-130=0$

$\sin x=0.27$

$\sin x=\mathrm{-0.55}$

$\tan x=\mathrm{-0.34}$

$\cos x=0.71$

${\tan }^{2}x+3\tan x-3=0$