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Translate into an algebraic equation and solve: The Pappas family has two cats, Zeus and Athena. Together, they weigh 13 pounds. Zeus weighs 6 pounds. How much does Athena weigh?

a + 6 = 13; Athena weighs 7 pounds.

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Translate into an algebraic equation and solve: Sam and Henry are roommates. Together, they have 68 books. Sam has 26 books. How many books does Henry have?

26 + h = 68; Henry has 42 books.

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Devise a problem-solving strategy.

  1. Read the problem. Make sure you understand all the words and ideas.
  2. Identify what you are looking for.
  3. Name what you are looking for. Choose a variable to represent that quantity.
  4. Translate into an equation. It may be helpful to restate the problem in one sentence with all the important information. Then, translate the English sentence into an algebra equation.
  5. Solve the equation using good algebra techniques.
  6. Check the answer in the problem and make sure it makes sense.
  7. Answer the question with a complete sentence.

Shayla paid $24,575 for her new car. This was $875 less than the sticker price. What was the sticker price of the car?

Solution

What are you asked to find? "What was the sticker price of the car?"
Assign a variable. Let s = the sticker price of the car.
Write a sentence that gives the information to find it. $24,575 is $875 less than the sticker price
$24,575 is $875 less than s
Translate into an equation. .
Solve. .
.
Check:
Is $875 less than $25,450 equal to $24,575?
25,450 875 = ? 24,575
24,575 = 24,575
Write a sentence that answers the question. The sticker price was $25,450.
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Translate into an algebraic equation and solve: Eddie paid $19,875 for his new car. This was $1,025 less than the sticker price. What was the sticker price of the car?

19,875 = s − 1025; the sticker price is $20,900.

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Translate into an algebraic equation and solve: The admission price for the movies during the day is $7.75 . This is $3.25 less than the price at night. How much does the movie cost at night?

7.75 = n − 3.25; the price at night is $11.00.

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Key concepts

  • Determine whether a number is a solution to an equation.
    1. Substitute the number for the variable in the equation.
    2. Simplify the expressions on both sides of the equation.
    3. Determine whether the resulting equation is true.
    If it is true, the number is a solution.
    If it is not true, the number is not a solution.
  • Subtraction and Addition Properties of Equality
    • Subtraction Property of Equality
      For all real numbers a, b, and c ,
      if a = b then a - c = b - c .
    • Addition Property of Equality
      For all real numbers a, b, and c ,
      if a = b then a + c = b + c .
  • Translate a word sentence to an algebraic equation.
    1. Locate the “equals” word(s). Translate to an equal sign.
    2. Translate the words to the left of the “equals” word(s) into an algebraic expression.
    3. Translate the words to the right of the “equals” word(s) into an algebraic expression.
  • Problem-solving strategy
    1. Read the problem. Make sure you understand all the words and ideas.
    2. Identify what you are looking for.
    3. Name what you are looking for. Choose a variable to represent that quantity.
    4. Translate into an equation. It may be helpful to restate the problem in one sentence with all the important information. Then, translate the English sentence into an algebra equation.
    5. Solve the equation using good algebra techniques.
    6. Check the answer in the problem and make sure it makes sense.
    7. Answer the question with a complete sentence.
Practice Key Terms 1

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Source:  OpenStax, Prealgebra. OpenStax CNX. Jul 15, 2016 Download for free at http://legacy.cnx.org/content/col11756/1.9
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