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Use the divergence theorem to compute flux integral S F · d S , where F ( x , y , z ) = x + y j + z 4 k and S is a part of cone z = x 2 + y 2 beneath top plane z = 1 , oriented downward.

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Use the divergence theorem to calculate surface integral S F · d S for F ( x , y , z ) = x 4 i x 3 z 2 j + 4 x y 2 z k , where S is the surface bounded by cylinder x 2 + y 2 = 1 and planes z = x + 2 and z = 0 .

S F · d S = 2 π 3

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Consider F ( x , y , z ) = x 2 i + x y j + ( z + 1 ) k . Let E be the solid enclosed by paraboloid z = 4 x 2 y 2 and plane z = 0 with normal vectors pointing outside E . Compute flux F across the boundary of E using the divergence theorem.

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For the following exercises, use a CAS along with the divergence theorem to compute the net outward flux for the fields across the given surfaces S .

[T] F = x , −2 y , 3 z ; S is sphere { ( x , y , z ) : x 2 + y 2 + z 2 = 6 } .

16 6 π

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[T] F = x , 2 y , z ; S is the boundary of the tetrahedron in the first octant formed by plane x + y + z = 1 .

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[T] F = y 2 x , x 3 y , y 2 z ; S is sphere { ( x , y , z ) : x 2 + y 2 + z 2 = 4 } .

128 3 π

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[T] F = x , y , z ; S is the surface of paraboloid z = 4 x 2 y 2 , for z 0 , plus its base in the xy -plane.

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For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D .

[T] F = z x , x y , 2 y z ; D is the region between spheres of radius 2 and 4 centered at the origin.

−703.7168

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[T] F = r | r | = x , y , z x 2 + y 2 + z 2 ; D is the region between spheres of radius 1 and 2 centered at the origin.

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[T] F = x 2 , y 2 , z 2 ; D is the region in the first octant between planes z = 4 x y and z = 2 x y .

20

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Let F ( x , y , z ) = 2 x i 3 x y j + x z 2 k . Use the divergence theorem to calculate S F · d S , where S is the surface of the cube with corners at ( 0 , 0 , 0 ) , ( 1 , 0 , 0 ) , ( 0 , 1 , 0 ) , ( 1 , 1 , 0 ) , ( 0 , 0 , 1 ) , ( 1 , 0 , 1 ) , ( 0 , 1 , 1 ) , and ( 1 , 1 , 1 ) , oriented outward.

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Use the divergence theorem to find the outward flux of field F ( x , y , z ) = ( x 3 3 y ) i + ( 2 y z + 1 ) j + x y z k through the cube bounded by planes x = ±1 , y = ±1 , and z = ±1 .

S F · d S = 8

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Let F ( x , y , z ) = 2 x i 3 y j + 5 z k and let S be hemisphere z = 9 x 2 y 2 together with disk x 2 + y 2 9 in the xy -plane. Use the divergence theorem.

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Evaluate S F · N d S , where F ( x , y , z ) = x 2 i + x y j + x 3 y 3 k and S is the surface consisting of all faces except the tetrahedron bounded by plane x + y + z = 1 and the coordinate planes, with outward unit normal vector N .

A vector field in three dimensions, with arrows becoming larger the further away from the origin they are, especially in their x components. S is the surface consisting of all faces except the tetrahedron bounded by the plane x + y + z = 1. As such, a portion of the given plane, the (x, y) plane, the (x, z) plane, and the (y, z) plane are shown. The arrows point towards the origin for negative x components, away from the origin for positive x components, down for positive x and negative y components, as well as positive y and negative x components, and for positive x and y components, as well as negative x and negative y components.

S F · N d S = 1 8

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Find the net outward flux of field F = b z c y , c x a z , a y b x across any smooth closed surface in R 3 , where a , b , and c are constants.

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Use the divergence theorem to evaluate S R R · n d s , where R ( x , y , z ) = x i + y j + z k and S is sphere x 2 + y 2 + z 2 = a 2 , with constant a > 0 .

S R R · n d s = 4 π a 4

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Use the divergence theorem to evaluate S F · d S , where F ( x , y , z ) = y 2 z i + y 3 j + x z k and S is the boundary of the cube defined by −1 x 1 , −1 y 1 , and 0 z 2 .

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Let R be the region defined by x 2 + y 2 + z 2 1 . Use the divergence theorem to find R z 2 d V .

R z 2 d V = 4 π 15

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Let E be the solid bounded by the xy -plane and paraboloid z = 4 x 2 y 2 so that S is the surface of the paraboloid piece together with the disk in the xy -plane that forms its bottom. If F ( x , y , z ) = ( x z sin ( y z ) + x 3 ) i + cos ( y z ) j + ( 3 z y 2 e x 2 + y 2 ) k , find S F · d S using the divergence theorem.

A vector field in three dimensions with all of the arrows pointing down. They seem to follow the path of the paraboloid drawn opening down with vertex at the origin. S is the surface of this paraboloid and the disk in the (x, y) plane that forms its bottom.
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Let E be the solid unit cube with diagonally opposite corners at the origin and (1, 1, 1), and faces parallel to the coordinate planes. Let S be the surface of E , oriented with the outward-pointing normal. Use a CAS to find S F · d S using the divergence theorem if F ( x , y , z ) = 2 x y i + 3 y e z j + x sin z k .

S F · d S = 6.5759

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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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