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This module discusses the graphing of exponential curves.

By plotting points, you can discover that the graph of y = 2 x size 12{y=2 rSup { size 8{x} } } {} looks like this:

Graph
y = 2 x size 12{y=2 rSup { size 8{x} } } {}

A few points to notice about this graph.

  • It goes through the point ( 0,1 ) size 12{ \( 0,1 \) } {} because 2 0 = 1 size 12{2 rSup { size 8{0} } =1} {} .
  • It never dips below the x size 12{x} {} -axis. The domain is unlimited, but the range is y>0. (*Think about our definitions of exponents: whether x size 12{x} {} is positive or negative, integer or fraction, 2 x size 12{2 rSup { size 8{x} } } {} is always positive.)
  • Every time you move one unit to the right, the graph height doubles. For instance, 2 5 size 12{2 rSup { size 8{5} } } {} is twice 2 4 size 12{2 rSup { size 8{4} } } {} , because it multiplies by one more 2. So as you move to the right, the y size 12{y} {} -values start looking like 8, 16, 32, 64, 128, and so on, going up more and more sharply.
  • Conversely, every time you move one unit to the left, the graph height drops in half. So as you move to the left, the y size 12{y} {} -values start looking like 1 2 size 12{ { {1} over {2} } } {} , 1 4 size 12{ { {1} over {4} } } {} , 1 8 size 12{ { {1} over {8} } } {} , and so on, falling closer and closer to 0.

What would the graph of y = 3 x size 12{y=3 rSup { size 8{x} } } {} look like? Of course, it would also go through ( 0,1 ) size 12{ \( 0,1 \) } {} because 3 0 = 1 size 12{3 rSup { size 8{0} } =1} {} . With each step to the right, it would triple ; with each step to the left, it would drop in a third . So the overall shape would look similar, but the rise (on the right) and the drop (on the left) would be faster.

Two overlapping exponential graph that intersect at (0,1)
y = 2 x size 12{y=2 rSup { size 8{x} } } {} in thin line; y = 3 x size 12{y=2 rSup { size 8{x} } } {} in thick line; They cross at ( 0,1 ) size 12{ \( 0,1 \) } {}

As you might guess, graphs such as 5 x size 12{5 rSup { size 8{x} } } {} and 10 x size 12{"10" rSup { size 8{x} } } {} all have this same characteristic shape. In fact, any graph a x size 12{a rSup { size 8{x} } } {} where a > 1 size 12{a>1} {} will look basically the same: starting at ( 0,1 ) size 12{ \( 0,1 \) } {} it will rise more and more sharply on the right, and drop toward zero on the left. This type of graph models exponential growth —functions that keep multiplying by the same number. A common example, which you work through in the text, is compound interest from a bank.

The opposite graph is 1 2 x size 12{ left ( { {1} over {2} } right ) rSup { size 8{x} } } {} .

Exponential graph with rising sharply to the left and drops towards zero towards the right.
y = 1 2 x size 12{y= left ( { {1} over {2} } right ) rSup { size 8{x} } } {}

Each time you move to the right on this graph, it multiplies by 1 2 size 12{ { {1} over {2} } } {} : in other words, it divides by 2, heading closer to zero the further you go. This kind of equation is used to model functions that keep dividing by the same number; for instance, radioactive decay. You will also be working through examples like this one.

Of course, all the permutations from the first chapter on “functions” apply to these graphs just as they apply to any graph. A particularly interesting example is 2 x size 12{2 rSup { size 8{ - x} } } {} . Remember that when you replace x size 12{x} {} with x size 12{ - x} {} , f ( 3 ) size 12{f \( 3 \) } {} becomes the old f ( 3 ) size 12{f \( - 3 \) } {} and vice-versa; in other words, the graph flips around the y size 12{y} {} -axis. If you take the graph of 2 x size 12{2 rSup { size 8{x} } } {} and permute it in this way, you get a familiar shape:

The graph flips around the y-axis
y = 2 x size 12{y=2 rSup { size 8{ - x} } } {}

Yes, it’s 1 2 x size 12{ left ( { {1} over {2} } right ) rSup { size 8{x} } } {} in a new disguise!

Why did it happen that way? Consider that 1 2 x = 1 x 2 x size 12{ left ( { {1} over {2} } right ) rSup { size 8{x} } = { {1 rSup { size 8{x} } } over {2 rSup { size 8{x} } } } } {} . But 1 x size 12{1 rSup { size 8{x} } } {} is just 1 (in other words, 1 to the anything is 1), so 1 2 x = 1 2 x size 12{ left ( { {1} over {2} } right ) rSup { size 8{x} } = { {1} over {2 rSup { size 8{x} } } } } {} . But negative exponents go in the denominator: 1 2 x size 12{ { {1} over {2 rSup { size 8{x} } } } } {} is the same thing as 2 x size 12{2 rSup { size 8{ - x} } } {} ! So we arrive at: 1 2 x = 2 x size 12{ left ( { {1} over {2} } right ) rSup { size 8{x} } =2 rSup { size 8{ - x} } } {} . The two functions are the same, so their graphs are of course the same.

Another fun pair of permutations is:

y = 2 2 x size 12{y=2 cdot 2 rSup { size 8{x} } } {} Looks just like y = 2 x size 12{y=2 rSup { size 8{x} } } {} but vertically stretched: all y­-values double

y = 2 x + 1 size 12{y=2 rSup { size 8{x+1} } } {} Looks just like y = 2 x size 12{y=2 rSup { size 8{x} } } {} but horizontally shifted: moves 1 to the left

If you permute 2 x size 12{2 rSup { size 8{x} } } {} in these two ways, you will find that they create the same graph.

Questions & Answers

What is inflation
Bright Reply
a general and ongoing rise in the level of prices in an economy
AI-Robot
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price
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appreciation
Eliyee
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In economics, a perfect market refers to a theoretical construct where all participants have perfect information, goods are homogenous, there are no barriers to entry or exit, and prices are determined solely by supply and demand. It's an idealized model used for analysis,
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Shukri Reply
other things being equal
AI-Robot
When MP₁ becomes negative, TP start to decline. Extuples Suppose that the short-run production function of certain cut-flower firm is given by: Q=4KL-0.6K2 - 0.112 • Where is quantity of cut flower produced, I is labour input and K is fixed capital input (K-5). Determine the average product of lab
Kelo
Extuples Suppose that the short-run production function of certain cut-flower firm is given by: Q=4KL-0.6K2 - 0.112 • Where is quantity of cut flower produced, I is labour input and K is fixed capital input (K-5). Determine the average product of labour (APL) and marginal product of labour (MPL)
Kelo
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Shukri
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Shukri
what is monopoly mean?
Habtamu Reply
What is different between quantity demand and demand?
Shukri Reply
Quantity demanded refers to the specific amount of a good or service that consumers are willing and able to purchase at a give price and within a specific time period. Demand, on the other hand, is a broader concept that encompasses the entire relationship between price and quantity demanded
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Economic growth as an increase in the production and consumption of goods and services within an economy.but Economic development as a broader concept that encompasses not only economic growth but also social & human well being.
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Jabir
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any question about economics?
Awais Reply
sir...I just want to ask one question... Define the term contract curve? if you are free please help me to find this answer 🙏
Asui
it is a curve that we get after connecting the pareto optimal combinations of two consumers after their mutually beneficial trade offs
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In economics, the contract curve refers to the set of points in an Edgeworth box diagram where both parties involved in a trade cannot be made better off without making one of them worse off. It represents the Pareto efficient allocations of goods between two individuals or entities, where neither p
Cornelius
In economics, the contract curve refers to the set of points in an Edgeworth box diagram where both parties involved in a trade cannot be made better off without making one of them worse off. It represents the Pareto efficient allocations of goods between two individuals or entities,
Cornelius
Suppose a consumer consuming two commodities X and Y has The following utility function u=X0.4 Y0.6. If the price of the X and Y are 2 and 3 respectively and income Constraint is birr 50. A,Calculate quantities of x and y which maximize utility. B,Calculate value of Lagrange multiplier. C,Calculate quantities of X and Y consumed with a given price. D,alculate optimum level of output .
Feyisa Reply
Answer
Feyisa
c
Jabir
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Source:  OpenStax, Advanced algebra ii: conceptual explanations. OpenStax CNX. May 04, 2010 Download for free at http://cnx.org/content/col10624/1.15
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