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Signals with stochastic, or random components may have an informative power spectral density (PSD).Estimation of the PSD of a stochastic signal requires averaging.The periodogram averages the magnitude spectra of smaller blocks of the signal to estimate the PSD.An alternative approach implicitly averages via windowing the auto-correlation of the signal to produce a low-variance smoothed spectral estimate.

Many signals are either partly or wholly stochastic, or random. Important examples include human speech, vibration in machines,and CDMA communication signals. Given the ever-present noise in electronic systems, it can be arguedthat almost all signals are at least partly stochastic. Such signals may have a distinct average spectral structure that reveals important information (such as for speechrecognition or early detection of damage in machinery). Spectrum analysis of any single block of data using window-based deterministic spectrum analysis , however, produces a random spectrum that may be difficult to interpret.For such situations, the classical statistical spectrum estimation methods described in this module can be used.

The goal in classical statistical spectrum analysis is to estimate X ω 2 , the power spectral density (PSD) across frequency of the stochastic signal.That is, the goal is to find the expected (mean, or average) energy density of the signal as a function of frequency.(For zero-mean signals, this equals the variance of each frequency sample.) Since the spectrum of each block of signal samples is itself random,we must average the squared spectral magnitudes over a number of blocks of data to find the mean.There are two main classical approaches, the periodogram and auto-correlation methods.

Periodogram method

The periodogram method divides the signal into a number of shorter (and often overlapped) blocks of data, computes the squared magnitudeof the windowed (and usually zero-padded ) DFT , X i ω k , of each block,and averages them to estimate the power spectral density. The squared magnitudes of the DFTs of L possibly overlapped length- N windowed blocks of signal (each probably with zero-padding ) are averaged to estimate the power spectral density: X ω k 1 L i L 1 X i ω k 2 For a fixed total number of samples, this introduces a tradeoff: Larger individual data blocks providesbetter frequency resolution due to the use of a longer window, but it means there are less blocks to average, so the estimatehas higher variance and appears more noisy. The best tradeoff depends on the application.Overlapping blocks by a factor of two to four increases the number of averages and reduces the variance, but since the same data is beingreused, still more overlapping does not further reduce the variance. As with any window-based spectrum estimation procedure, the window function introduces broadening and sidelobes into the power spectrumestimate. That is, the periodogram produces an estimate of the windowed spectrum X ω X ω W M 2 , not of X ω 2 .

shows the non-negative frequencies of the DFT (zero-padded to 1024 total samples) of 64 samples of areal-valued stochastic signal.

DFT magnitude (in dB) of 64 samples of a stochastic signal
With no averaging, the power spectrum is very noisy and difficult to interpret other than noting a significant reduction in spectral energyabove about half the Nyquist frequency. Various peaks and valleys appear in the lower frequencies,but it is impossible to say from this figure whether they represent actual structure in the power spectral density (PSD)or simply random variation in this single realization. shows the same frequencies of a length-1024 DFT of a length-1024 signal. While the frequency resolution has improved,there is still no averaging, so it remains difficult to understand the power spectral density of this signal.Certain small peaks in frequency might represent narrowband components in the spectrum, or may just be random noise peaks.

DFT magnitude (in dB) of 1024 samples of a stochastic signal
In , a power spectral density computed from averaging the squared magnitudes of length-1024 zero-padded DFTs of 508 length-64blocks of data (overlapped by a factor of four, or a 16-sample step between blocks) are shown.

Power spectrum density estimate (in dB) of 1024 samples of a stochastic signal
While the frequency resolution corresponds to that of a length-64 truncation window, the averaging greatlyreduces the variance of the spectral estimate and allows the user to reliably conclude that the signal consists of lowpass broadband noisewith a flat power spectrum up to half the Nyquist frequency, with a stronger narrowband frequency component at around 0.65 radians.

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Auto-correlation-based approach

The averaging necessary to estimate a power spectral density can be performed in the discrete-time domain, rather than in frequency,using the auto-correlation method. The squared magnitude of the frequency response,from the DTFT multiplication and conjugation properties, corresponds in the discrete-time domain to the signal convolvedwith the time-reverse of itself, X ω 2 X ω X * ω x n x * n r n or its auto-correlation r n k x k x * n k We can thus compute the squared magnitude of the spectrum of a signal by computingthe DFT of its auto-correlation. For stochastic signals, the power spectral densityis an expectation, or average, and by linearity of expectation can be found by transforming theaverage of the auto-correlation. For a finite block of N signal samples, the average of the autocorrelation values, r n , is r n 1 N n k N 1 n 0 x k x * n k Note that with increasing lag , n , fewer values are averaged, so they introducemore noise into the estimated power spectrum. By windowing the auto-correlation before transforming it to the frequency domain, aless noisy power spectrum is obtained, at the expense of less resolution.The multiplication property of the DTFT shows that the windowing smooths the resulting powerspectrum via convolution with the DTFT of the window: X ω n M M r n w n ω n X ω 2 W ω This yields another important interpretation of how the auto-correlation method works: it estimates the power spectral density by averaging the power spectrum over nearby frequencies , through convolution with the window function's transform,to reduce variance. Just as with the periodogram approach, there is always avariance vs. resolution tradeoff. The periodogram and the auto-correlation method givesimilar results for a similar amount of averaging; the user should simply note that in the periodogram case, the window introduces smoothingof the spectrum via frequency convolution before squaring the magnitude, whereas the periodogram convolves the squared magnitude with W ω .

Questions & Answers

Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Kate Reply
what is the change in momentum of a body?
Eunice Reply
what is a capacitor?
Raymond Reply
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
Maria Reply
please solve
Sharon
8m/s²
Aishat
What is Thermodynamics
Muordit
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
Saheed Reply
50 m/s due south east
Someone
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
Ramon Reply
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
Someone
definitely of physics
Haryormhidey Reply
how many start and codon
Esrael Reply
what is field
Felix Reply
physics, biology and chemistry this is my Field
ALIYU
field is a region of space under the influence of some physical properties
Collete
what is ogarnic chemistry
WISDOM Reply
determine the slope giving that 3y+ 2x-14=0
WISDOM
Another formula for Acceleration
Belty Reply
a=v/t. a=f/m a
IHUMA
innocent
Adah
pratica A on solution of hydro chloric acid,B is a solution containing 0.5000 mole ofsodium chlorid per dm³,put A in the burret and titrate 20.00 or 25.00cm³ portion of B using melting orange as the indicator. record the deside of your burret tabulate the burret reading and calculate the average volume of acid used?
Nassze Reply
how do lnternal energy measures
Esrael
Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
JALLAH Reply
No. According to Isac Newtons law. this two bodies maybe you and the wall beside you. Attracting depends on the mass och each body and distance between them.
Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Robert
like charges repel while unlike charges atttact
Raymond
What is specific heat capacity
Destiny Reply
Specific heat capacity is a measure of the amount of energy required to raise the temperature of a substance by one degree Celsius (or Kelvin). It is measured in Joules per kilogram per degree Celsius (J/kg°C).
AI-Robot
specific heat capacity is the amount of energy needed to raise the temperature of a substance by one degree Celsius or kelvin
ROKEEB
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Source:  OpenStax, The dft, fft, and practical spectral analysis. OpenStax CNX. Feb 22, 2007 Download for free at http://cnx.org/content/col10281/1.2
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