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In this figure, structural formulas are used to illustrate a chemical reaction, including an intermediate step. On the left, a structural formula for cyclobutane is shown. This structure is composed of 4 C atoms connected with single bonds in a square shape. Each C atom is bonded to two other C atoms in the structure, leaving two bonds for H atoms pointing outward above, below, left, and right. This structure is labeled, “Cyclohexane.” An arrow points right to a similar structure which has the upper and lower bonds replaced by rows of 4 dots. Similarly, columns of 3 dots appear just inside the line segments indicating the vertically oriented single bonds in the structure. The label “Activated complex” appears beneath this structure. A second arrow points right to two identical ethane molecules with a plus symbol between them. Each of these molecules contains two C atoms connected with a double bond oriented vertically between them. The C atom at the top of these molecules has H atoms bonded above to the right and left. Similarly, the lower C atom has two H atoms bonded below to the right and left. Below these two molecules appears the label “Ethylene.”

In a sample of C 4 H 8 , a few of the rapidly moving C 4 H 8 molecules collide with other rapidly moving molecules and pick up additional energy. When the C 4 H 8 molecules gain enough energy, they can transform into an activated complex, and the formation of ethylene molecules can occur. In effect, a particularly energetic collision knocks a C 4 H 8 molecule into the geometry of the activated complex. However, only a small fraction of gas molecules travel at sufficiently high speeds with large enough kinetic energies to accomplish this. Hence, at any given moment, only a few molecules pick up enough energy from collisions to react.

The rate of decomposition of C 4 H 8 is directly proportional to its concentration. Doubling the concentration of C 4 H 8 in a sample gives twice as many molecules per liter. Although the fraction of molecules with enough energy to react remains the same, the total number of such molecules is twice as great. Consequently, there is twice as much C 4 H 8 per liter, and the reaction rate is twice as fast:

rate = Δ [ C 4 H 8 ] Δ t = k [ C 4 H 8 ]

A similar relationship applies to any unimolecular elementary reaction; the reaction rate is directly proportional to the concentration of the reactant, and the reaction exhibits first-order behavior. The proportionality constant is the rate constant for the particular unimolecular reaction.

Bimolecular elementary reactions

The collision and combination of two molecules or atoms to form an activated complex in an elementary reaction is called a bimolecular reaction    . There are two types of bimolecular elementary reactions:

A + B products and 2 A products

For the first type, in which the two reactant molecules are different, the rate law is first-order in A and first order in B :

rate = k [ A ] [ B ]

For the second type, in which two identical molecules collide and react, the rate law is second order in A :

rate = k [ A ] [ A ] = k [ A ] 2

Some chemical reactions have mechanisms that consist of a single bimolecular elementary reaction. One example is the reaction of nitrogen dioxide with carbon monoxide:

NO 2 ( g ) + CO ( g ) NO ( g ) + CO 2 ( g )

Another is the decomposition of two hydrogen iodide molecules to produce hydrogen, H 2 , and iodine, I 2 [link] :

2HI ( g ) H 2 ( g ) + I 2 ( g )
This figure provides an illustration of a reaction between two H I molecules using space filling models. H atoms are shown as white spheres, and I atoms are shown as purple spheres. On the left, two H I molecules are shownwith a small white sphere bonded to a much larger purple sphere. The label, “Two H I molecules,” appears below. An arrow points right to a similar structure in which the two molecules appear pushed together, so that the purple spheres of the two molecules are touching. Below appears the label, “Transition state.” Following another arrow, two white spheres are shown vertically oriented and bonded together with the label, “H subscript 2” above. The H subscript 2 molecule is followed by a plus sign and two purple spheres bonded together with the label, “I subscript 2” above. Below these structures is the label, “Hydrogen iodide molecules decompose to produce hydrogen H subscript 2 and iodine I subscript 2.”
The probable mechanism for the dissociation of two HI molecules to produce one molecule of H 2 and one molecule of I 2 .

Bimolecular elementary reactions may also be involved as steps in a multistep reaction mechanism. The reaction of atomic oxygen with ozone is one example:

O ( g ) + O 3 ( g ) 2O 2 ( g )

Termolecular elementary reactions

An elementary termolecular reaction    involves the simultaneous collision of three atoms, molecules, or ions. Termolecular elementary reactions are uncommon because the probability of three particles colliding simultaneously is less than one one-thousandth of the probability of two particles colliding. There are, however, a few established termolecular elementary reactions. The reaction of nitric oxide with oxygen appears to involve termolecular steps:

2NO + O 2 2 NO 2 rate = k [ NO ] 2 [ O 2 ]

Likewise, the reaction of nitric oxide with chlorine appears to involve termolecular steps:

Questions & Answers

Ayele, K., 2003. Introductory Economics, 3rd ed., Addis Ababa.
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Ariel
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Ariel
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AI-Robot
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Abdulraufu
Suppose the demand function that a firm faces shifted from Qd  120 3P to Qd  90  3P and the supply function has shifted from QS  20  2P to QS 10  2P . a) Find the effect of this change on price and quantity. b) Which of the changes in demand and supply is higher?
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Jan
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Milan
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out-of-pocket costs for a firm, for example, payments for wages and salaries, rent, or materials
AI-Robot
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Source:  OpenStax, Chemistry. OpenStax CNX. May 20, 2015 Download for free at http://legacy.cnx.org/content/col11760/1.9
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