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By the end of this section, you will be able to:
  • Explain the characterization of aqueous solutions as acidic, basic, or neutral
  • Express hydronium and hydroxide ion concentrations on the pH and pOH scales
  • Perform calculations relating pH and pOH

As discussed earlier, hydronium and hydroxide ions are present both in pure water and in all aqueous solutions, and their concentrations are inversely proportional as determined by the ion product of water ( K w ). The concentrations of these ions in a solution are often critical determinants of the solution’s properties and the chemical behaviors of its other solutes, and specific vocabulary has been developed to describe these concentrations in relative terms. A solution is neutral    if it contains equal concentrations of hydronium and hydroxide ions; acidic    if it contains a greater concentration of hydronium ions than hydroxide ions; and basic    if it contains a lesser concentration of hydronium ions than hydroxide ions.

A common means of expressing quantities, the values of which may span many orders of magnitude, is to use a logarithmic scale. One such scale that is very popular for chemical concentrations and equilibrium constants is based on the p-function, defined as shown where “X” is the quantity of interest and “log” is the base-10 logarithm:

pX = −log X

The pH    of a solution is therefore defined as shown here, where [H 3 O + ] is the molar concentration of hydronium ion in the solution:

pH = −log [ H 3 O + ]

Rearranging this equation to isolate the hydronium ion molarity yields the equivalent expression:

[ H 3 O + ] = 10 −pH

Likewise, the hydroxide ion molarity may be expressed as a p-function, or pOH    :

pOH = −log [ OH ]

or

[ OH ] = 10 −pOH

Finally, the relation between these two ion concentration expressed as p-functions is easily derived from the K w expression:

K w = [ H 3 O + ] [ OH ]
−log K w = −log ( [ H 3 O + ] [ OH ] ) = −log [ H 3 O + ] + −log [ OH ]
p K w = pH + pOH

At 25 °C, the value of K w is 1.0 × 10 −14 , and so:

14.00 = pH + pOH

As was shown in [link] , the hydronium ion molarity in pure water (or any neutral solution) is 1.0 × 10 −7 M at 25 °C. The pH and pOH of a neutral solution at this temperature are therefore:

pH = −log [ H 3 O + ] = −log ( 1.0 × 1 0 −7 ) = 7.00
pOH = −log [ OH ] = −log ( 1.0 × 1 0 −7 ) = 7.00

And so, at this temperature , acidic solutions are those with hydronium ion molarities greater than 1.0 × 10 −7 M and hydroxide ion molarities less than 1.0 × 10 −7 M (corresponding to pH values less than 7.00 and pOH values greater than 7.00). Basic solutions are those with hydronium ion molarities less than 1.0 × 10 −7 M and hydroxide ion molarities greater than 1.0 × 10 −7 M (corresponding to pH values greater than 7.00 and pOH values less than 7.00).

Since the autoionization constant K w is temperature dependent, these correlations between pH values and the acidic/neutral/basic adjectives will be different at temperatures other than 25 °C. For example, the “Check Your Learning” exercise accompanying [link] showed the hydronium molarity of pure water at 80 °C is 4.9 × 10 −7 M , which corresponds to pH and pOH values of:

pH = −log [ H 3 O + ] = −log ( 4.9 × 10 −7 ) = 6.31
pOH = −log [ OH ] = −log ( 4.9 × 10 −7 ) = 6.31

Questions & Answers

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can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
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Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
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Source:  OpenStax, Chemistry. OpenStax CNX. May 20, 2015 Download for free at http://legacy.cnx.org/content/col11760/1.9
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