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The region D is shown in the following figure. Evaluate the double integral D ( x 2 + y ) d A by using the easier order of integration.

A region is bounded by y = negative 4 + x squared and y = 4 minus x squared.
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The region D is given in the following figure. Evaluate the double integral D ( x 2 y 2 ) d A by using the easier order of integration.

A region is bounded by y to the fourth power = 1 minus x and y to the fourth power = 1 + x.

D ( x 2 y 2 ) d A = −1 1 y 4 1 1 y 4 ( x 2 y 2 ) d x d y = 464 4095

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Find the volume of the solid under the surface z = 2 x + y 2 and above the region bounded by y = x 5 and y = x .

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Find the volume of the solid under the plane z = 3 x + y and above the region determined by y = x 7 and y = x .

4 5

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Find the volume of the solid under the plane z = x y and above the region bounded by x = tan y , x = tan y , and x = 1 .

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Find the volume of the solid under the surface z = x 3 and above the plane region bounded by x = sin y , x = sin y , and x = 1 .

5 π 32

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Let g be a positive, increasing, and differentiable function on the interval [ a , b ] . Show that the volume of the solid under the surface z = g ( x ) and above the region bounded by y = 0 , y = g ( x ) , x = a , and x = b is given by 1 2 ( g 2 ( b ) g 2 ( a ) ) .

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Let g be a positive, increasing, and differentiable function on the interval [ a , b ] , and let k be a positive real number. Show that the volume of the solid under the surface z = g ( x ) and above the region bounded by y = g ( x ) , y = g ( x ) + k , x = a , and x = b is given by k ( g ( b ) g ( a ) ) .

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Find the volume of the solid situated in the first octant and determined by the planes z = 2 , z = 0 , x + y = 1 , x = 0 , and y = 0 .

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Find the volume of the solid situated in the first octant and bounded by the planes x + 2 y = 1 , x = 0 , y = 0 , z = 4 , and z = 0 .

1

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Find the volume of the solid bounded by the planes x + y = 1 , x y = 1 , x = 0 , z = 0 , and z = 10 .

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Find the volume of the solid bounded by the planes x + y = 1 , x y = 1 , x + y = −1 , x y = −1 , z = 1 and z = 0 .

2

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Let S 1 and S 2 be the solids situated in the first octant under the planes x + y + z = 1 and x + y + 2 z = 1 , respectively, and let S be the solid situated between S 1 , S 2 , x = 0 , and y = 0 .

  1. Find the volume of the solid S 1 .
  2. Find the volume of the solid S 2 .
  3. Find the volume of the solid S by subtracting the volumes of the solids S 1 and S 2 .
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Let S 1 and S 2 be the solids situated in the first octant under the planes 2 x + 2 y + z = 2 and x + y + z = 1 , respectively, and let S be the solid situated between S 1 , S 2 , x = 0 , and y = 0 .

  1. Find the volume of the solid S 1 .
  2. Find the volume of the solid S 2 .
  3. Find the volume of the solid S by subtracting the volumes of the solids S 1 and S 2 .

a. 1 3 ; b. 1 6 ; c. 1 6

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Let S 1 and S 2 be the solids situated in the first octant under the plane x + y + z = 2 and under the sphere x 2 + y 2 + z 2 = 4 , respectively. If the volume of the solid S 2 is 4 π 3 , determine the volume of the solid S situated between S 1 and S 2 by subtracting the volumes of these solids.

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Let S 1 and S 2 be the solids situated in the first octant under the plane x + y + z = 2 and bounded by the cylinder x 2 + y 2 = 4 , respectively.

  1. Find the volume of the solid S 1 .
  2. Find the volume of the solid S 2 .
  3. Find the volume of the solid S situated between S 1 and S 2 by subtracting the volumes of the solids S 1 and S 2 .

a. 4 3 ; b. 2 π ; c. 6 π 4 3

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[T] The following figure shows the region D bounded by the curves y = sin x , x = 0 , and y = x 4 . Use a graphing calculator or CAS to find the x -coordinates of the intersection points of the curves and to determine the area of the region D . Round your answers to six decimal places.

A region is bounded by y = sin x, y = x to the fourth power, and x = 0.
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[T] The region D bounded by the curves y = cos x , x = 0 , and y = x 3 is shown in the following figure. Use a graphing calculator or CAS to find the x -coordinates of the intersection points of the curves and to determine the area of the region D . Round your answers to six decimal places.

A region is bounded by y = cos x, y = x cubed, and x = 0.

0 and 0.865474 ; A ( D ) = 0.621135

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Suppose that ( X , Y ) is the outcome of an experiment that must occur in a particular region S in the x y -plane. In this context, the region S is called the sample space of the experiment and X and Y are random variables. If D is a region included in S , then the probability of ( X , Y ) being in D is defined as P [ ( X , Y ) D ] = D p ( x , y ) d x d y , where p ( x , y ) is the joint probability density of the experiment. Here, p ( x , y ) is a nonnegative function for which S p ( x , y ) d x d y = 1 . Assume that a point ( X , Y ) is chosen arbitrarily in the square [ 0 , 3 ] × [ 0 , 3 ] with the probability density

p ( x , y ) = { 1 9 ( x , y ) [ 0 , 3 ] × [ 0 , 3 ] , 0 otherwise .

Find the probability that the point ( X , Y ) is inside the unit square and interpret the result.

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Consider X and Y two random variables of probability densities p 1 ( x ) and p 2 ( x ) , respectively. The random variables X and Y are said to be independent if their joint density function is given by p ( x , y ) = p 1 ( x ) p 2 ( y ) . At a drive-thru restaurant, customers spend, on average, 3 minutes placing their orders and an additional 5 minutes paying for and picking up their meals. Assume that placing the order and paying for/picking up the meal are two independent events X and Y . If the waiting times are modeled by the exponential probability densities

p 1 ( x ) = { 1 3 e x / 3 x 0 , 0 otherwise, and p 2 ( y ) = { 1 5 e y / 5 y 0 , 0 otherwise,

respectively, the probability that a customer will spend less than 6 minutes in the drive-thru line is given by P [ X + Y 6 ] = D p ( x , y ) d x d y , where D = { ( x , y ) } | x 0 , y 0 , x + y 6 } . Find P [ X + Y 6 ] and interpret the result.

P [ X + Y 6 ] = 1 + 3 2 e 2 5 e 6 / 5 0.45 ; there is a 45 % chance that a customer will spend 6 minutes in the drive-thru line.

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[T] The Reuleaux triangle consists of an equilateral triangle and three regions, each of them bounded by a side of the triangle and an arc of a circle of radius s centered at the opposite vertex of the triangle. Show that the area of the Reuleaux triangle in the following figure of side length s is s 2 2 ( π 3 ) .

An equilateral triangle with additional regions consisting of three arcs of a circle with radius equal to the length of the side of the triangle. These arcs connect two adjacent vertices, and the radius is taken from the opposite vertex.
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[T] Show that the area of the lunes of Alhazen , the two blue lunes in the following figure, is the same as the area of the right triangle ABC . The outer boundaries of the lunes are semicircles of diameters A B and A C , respectively, and the inner boundaries are formed by the circumcircle of the triangle A B C .

A right triangle with points A, B, and C. Point B has the right angle. There are two lunes drawn from A to B and from B to C with outer diameters AB and AC, respectively, and with the inner boundaries formed by the circumcircle of the triangle ABC.
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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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