1.2 Order of operations for whole numbers  (Page 2/2)

8 + (32 – 7)

(34 + 18 – 2 · 3) + 11

8(10) + 4(2 + 3) – (20 + 3 · 15 + 40 – 5)

5 · 8 + 42 – 22

4(6 ² – 3 ³ ) ÷ (4 ² – 4)

(8 + 9 · 3) ÷ 7 + 5 · (8 ÷ 4 + 7 + 3 · 5)

$\frac{3^3+2^3}{6^2-\text{29}}+5\left(\frac{8^2+2^4}{7^2-3^2}\right)÷\frac{8\cdot 3+1^8}{2^3-3}$

$2+3\cdot (8)$

$1-5(8-8)$

$\text{37}-1\cdot 6^2$

$\text{98}÷2÷7^2$

$(4^2-2\cdot 4)-2^3$

$\text{61}-\text{22}+4[3\cdot (\text{10})+\text{11}]$

$\text{121}-4\cdot [(4)\cdot (5)-\text{12}]+\frac{\text{16}}{2}$

$2^2\cdot 3+2^3(6-2)-(3+\text{17})+\text{11}(6)$

$\frac{8(6+\text{20})}{8}+\frac{3(6+\text{16})}{\text{22}}$

$\frac{(1+\text{16})-3}{7}+5(\text{12})$

$1^6+0^8+5^2(2+8{)}^3$

$\frac{5(8^2-9\cdot 6)}{2^5-7}+\frac{7^2-4^2}{2^4-5}$

$6\{2\cdot 8+3\}-(5)\cdot (2)+\frac{8}{4}+(1+8)\cdot (1+\text{11})$

$\text{26}-2\cdot \left\{\frac{6+\text{20}}{\text{13}}\right\}$

$(\text{10}+5)\cdot (\text{10}+5)-4\cdot (\text{60}-4)$

$\frac{6^2-1}{2^3-3}+\frac{4^3+2\cdot 3}{2\cdot 5}$

$\frac{\text{51}}{\text{17}}+7-2\cdot 5\cdot \left(\frac{\text{12}}{3}\right)$

$(\text{21}-3)\cdot (6-1)\cdot \left(6\right)+4(6+3)$

$\frac{(2+1{)}^3+2^3+1^{\text{10}}}{6^2}-\frac{{\text{15}}^2-[2\cdot 5{]}^2}{5\cdot 5^2}$