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Plot the data

The statement in Listing 3 calls the overloaded plotData method to cause all of the pages belonging to the plotting object titled "A" to be stacked in alocation where the upper left corner of the stack is 401 pixels to the right of the upper left corner of the screen.

Listing 3. Plot the data.
plotObjectA.plotData(401,0);

As described earlier, page 0 containing the earliest data fed to the plotting object is on the top of the stack. Figure 1 shows the two pages belonging to this plotting object after they have been manually rearranged to make them bothvisible.

Feed and plot the object titled "B"

Listing 4 feeds 2600 random white noise values to the object titled "B" and displays the pages in the default location in the upper left corner of thescreen. Listing 4 also signals the end of the main method.

Listing 4. Feed and plot the object titled "B".
for(int cnt = 0;cnt<2600;cnt++){ plotObjectB.feedData((Math.random() - 0.5)*25); }//end for loopplotObjectB.plotData();}//end main

Listing 4 (plus one of the statements in Listing 1 ) is much more typical of the amount of code required to use this plotting class than was thecase with Listing 2 .

(Almost all of the code in Listing 2 was required to set the special data values used to test the transitions discussed earlier.)

The three steps

To recap, the three steps required to use this class for plotting nearly unlimited amounts of data are:

  1. Instantiate a plotting object of the class named PlotALot01 , as in Listing 1 .
  2. Call the feedData method once for each data value that is to be plotted, as in Listing 4 .
  3. Call the plotData method on the plotting object afterall of the data has been fed to the plotting object, as in Listing 3 or Listing 4 .

Some instance variables

Continuing with the class definition for the class named PlotALot01 , Listing 5 shows several instance variables that belong to a plotting object instantiatedfrom this class.

Listing 5. Some instance variables.
String title; int frameWidth;int frameHeight; int traceSpacing;//pixels between tracesint sampSpacing;//pixels between samples int ovalWidth;//width of sample marking ovalint ovalHeight;//height of sample marking ovalint tracesPerPage; int samplesPerPage;int pageCounter = 0; int sampleCounter = 0;ArrayList<Page>pageLinks = new ArrayList<Page>();

The purpose of each of these instance variables is indicated by the name of the variable, and in some cases by the comments following the variabledeclaration. In addition, I will have more to say about some of these variables later when I discuss the code that uses them.

(Note the use of generics in the declaration and initialization of the variable named pageLinks . The use of generics dictates that this class requires J2SE 5.0 or later.)

The first overloaded constructor

As mentioned earlier, there are two overloaded versions of the constructor for this class. The overloaded version that begins in Listing 6 accepts several incoming parameters allowing the user to control various aspects of the plottingformat.

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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