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Inleiding

In graad 10 het ons gekyk na die oplos van lineêre vergelykings, kwadratiese vergelykings, eksponentieële vergelykings en lineêre ongelykhede. Hierdie hoofstuk bo op daardie werk. Ons kyk na verskillende metodes om kwadratiese vergelykings om te los.

Oplos deur faktorisering

Die oplos van kwadratiese vergelylings deur faktorisering was behandel in Graad 10. Kom ons doen gou 'n voorbeeld om jou geheue te verfris.

Losop die vergelyking, 2 x 2 - 5 x - 12 = 0 .

  1. Hierdie vergelyking het geen gemene faktore nie.

  2. Die verglyking is in die voorgeskrewe vorm, met a = 2 , b = - 5 en c = - 12 .

  3. 2 x 2 - 5 x - 12 het faktore van die vorm:

    ( 2 x + s ) ( x + v )

    met s en v konstantes wat bepaal moet word. Dit word vermenigvuldig om

    2 x 2 + ( s + 2 v ) x + s v

    te gee. Ons sien dat s v = - 12 en s + 2 v = - 5 . Hierdie is 'n stel gelyktydige vergelykings in s en v , dit is maklik om numeries op te los. Al die opsies vir s en v word hieronder oorweeg.

    s v s + 2 v
    2 -6 -10
    -2 6 10
    3 -4 -5
    -3 4 5
    4 -3 -2
    -4 3 2
    6 -2 2
    -6 2 -2

    Ons sien dat die kombinasie van s = 3 en v = - 4 gee vir ons s + 2 v = - 5 .

  4. ( 2 x + 3 ) ( x - 4 ) = 0
  5. Indien twee hakkies vermenigvuldig word en 0 gee, moet een van die hakkies 0 wees, dus

    2 x + 3 = 0

    of

    x - 4 = 0

    Dus, x = - 3 2 of x = 4

  6. Die oplossing van 2 x 2 - 5 x - 12 = 0 is x = - 3 2 of x = 4 .

Dit is belangrik om te onthou dat 'n kwadratiese vergelyking in die vorm a x 2 + b x + c = 0 moet wees voor ons dit kan op los met die metodes.

Los op a : a ( a - 3 ) = 10

  1. Verwyder die hakkies en kry al die terme aan een kant van die gelykaanteken.

    a 2 - 3 a - 10 = 0
  2. ( a + 2 ) ( a - 5 ) = 0
  3. a + 2 = 0

    of

    a - 5 = 0

    Los die twee lineêre vergelykings op en kontroleer die antwoorde in die oorspronklike vergelyking.

  4. Dus, a = - 2 of a = 5

Los op b : 3 b b + 2 + 1 = 4 b + 1

  1. 3 b ( b + 1 ) + ( b + 2 ) ( b + 1 ) ( b + 2 ) ( b + 1 ) = 4 ( b + 2 ) ( b + 2 ) ( b + 1 )
  2. Die noemers is dieselfde, daarom moet die tellers ook dieselfde wees.

    Maar b - 2 en b - 1

  3. 3 b 2 + 3 b + b 2 + 3 b + 2 = 4 b + 8 4 b 2 + 2 b - 6 = 0 2 b 2 + b - 3 = 0
  4. ( 2 b + 3 ) ( b - 1 ) = 0 2 b + 3 = 0 o f b - 1 = 0 b = - 3 2 o f b = 1
  5. Albei oplossing is geldig

    Dus, b = - 3 2 of b = 1

Oplossing deur faktorisering

Los op die volgende kwadratiese vergelykings op deur faktorisering. Sommige van die antwoorde kan gelos word in die wortel vorm.

  1. 2 y 2 - 61 = 101
  2. 2 y 2 - 10 = 0
  3. y 2 - 4 = 10
  4. 2 y 2 - 8 = 28
  5. 7 y 2 = 28
  6. y 2 + 28 = 100
  7. 7 y 2 + 14 y = 0
  8. 12 y 2 + 24 y + 12 = 0
  9. 16 y 2 - 400 = 0
  10. y 2 - 5 y + 6 = 0
  11. y 2 + 5 y - 36 = 0
  12. y 2 + 2 y = 8
  13. - y 2 - 11 y - 24 = 0
  14. 13 y - 42 = y 2
  15. y 2 + 9 y + 14 = 0
  16. y 2 - 5 k y + 4 k 2 = 0
  17. y ( 2 y + 1 ) = 15
  18. 5 y y - 2 + 3 y + 2 = - 6 y 2 - 2 y
  19. y - 2 y + 1 = 2 y + 1 y - 7

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When MP₁ becomes negative, TP start to decline. Extuples Suppose that the short-run production function of certain cut-flower firm is given by: Q=4KL-0.6K2 - 0.112 • Where is quantity of cut flower produced, I is labour input and K is fixed capital input (K-5). Determine the average product of lab
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Extuples Suppose that the short-run production function of certain cut-flower firm is given by: Q=4KL-0.6K2 - 0.112 • Where is quantity of cut flower produced, I is labour input and K is fixed capital input (K-5). Determine the average product of labour (APL) and marginal product of labour (MPL)
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Quantity demanded refers to the specific amount of a good or service that consumers are willing and able to purchase at a give price and within a specific time period. Demand, on the other hand, is a broader concept that encompasses the entire relationship between price and quantity demanded
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In economics, the contract curve refers to the set of points in an Edgeworth box diagram where both parties involved in a trade cannot be made better off without making one of them worse off. It represents the Pareto efficient allocations of goods between two individuals or entities,
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Suppose a consumer consuming two commodities X and Y has The following utility function u=X0.4 Y0.6. If the price of the X and Y are 2 and 3 respectively and income Constraint is birr 50. A,Calculate quantities of x and y which maximize utility. B,Calculate value of Lagrange multiplier. C,Calculate quantities of X and Y consumed with a given price. D,alculate optimum level of output .
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Answer
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c
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Source:  OpenStax, Siyavula textbooks: wiskunde (graad 11). OpenStax CNX. Sep 20, 2011 Download for free at http://cnx.org/content/col11339/1.4
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