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207 g of lead combines with oxygen to form 239 g of a lead oxide. Use this information to work out the formula of the lead oxide (Relative atomic masses: Pb = 207 u and O = 16 u ).

  1. 239 - 207 = 32 g
  2. n = m M

    Lead

    207 207 = 1 mol

    Oxygen

    32 16 = 2 mol
  3. The mole ratio of Pb : O in the product is 1:2, which means that for every atom of lead, there will be two atoms of oxygen. The formula of the compound is PbO 2 .

Vinegar, which is used in our homes, is a dilute form of acetic acid. A sample of acetic acid has the following percentage composition: 39,9% carbon, 6,7% hyrogen and 53,4% oxygen.

  1. Determine the empirical formula of acetic acid.
  2. Determine the molecular formula of acetic acid if the molar mass of acetic acid is 60 g · mol - 1 .
  1. In 100 g of acetic acid, there is 39,9 g C , 6,7 g H and 53,4 g O

  2. n = m M

    n C = 39 , 9 12 = 3 , 33 mol n H = 6 , 7 1 = 6 , 7 mol n O = 53 , 4 16 = 3 , 34 mol
  3. Empirical formula is CH 2 O

  4. The molar mass of acetic acid using the empirical formula is 30 g · mol - 1 . Therefore the actual number of moles of each element must be double what it is in the empirical formula.

    The molecular formula is therefore C 2 H 4 O 2 or CH 3 COOH

Aluminium trichloride ( AlCl 3 ) is an ionic substance that forms crystals in the solid phase. Water molecules may be trapped inside the crystal lattice. We represent this as: AlCl 3 · n H 2 O . A learner heated some aluminium trichloride crystals until all the water had evaporated and found that the mass after heating was 2,8 g . The mass before heating was 5 g . What is the number of moles of water molecules in the aluminium trichloride?

  1. We first need to find n, the number of water molecules that are present in the crystal. To do this we first note that the mass of water lost is 5 - 2,8 = 2,2 .

  2. The next step is to work out the mass ratio of aluminium trichloride to water and the mole ratio. The mass ratio is:

    2,8 : 2,2
    To work out the mole ratio we divide the mass ratio by the molecular mass of each species:
    2,8 133 : 2,2 18 = 0,021 : 0,12
    Next we do the following:
    0,021 1 0,021 = 1
    and
    0,12 0,021 = 6
    So the mole ratio of aluminium trichloride to water is:
    1 : 6

  3. And now we know that there are 6 moles of water molecules in the crystal.

Khan academy video on molecular and empirical formulae - 1

Khan academy video on mass composition - 1

Moles and empirical formulae

  1. Calcium chloride is produced as the product of a chemical reaction.
    1. What is the formula of calcium chloride?
    2. What percentage does each of the elements contribute to the mass of a molecule of calcium chloride?
    3. If the sample contains 5 g of calcium chloride, what is the mass of calcium in the sample?
    4. How many moles of calcium chloride are in the sample?
  2. 13 g of zinc combines with 6,4 g of sulphur. What is the empirical formula of zinc sulphide?
    1. What mass of zinc sulphide will be produced?
    2. What percentage does each of the elements in zinc sulphide contribute to its mass?
    3. Determine the formula of zinc sulphide.
  3. A calcium mineral consisted of 29,4% calcium, 23,5% sulphur and 47,1% oxygen by mass. Calculate the empirical formula of the mineral.
  4. A chlorinated hydrocarbon compound was analysed and found to consist of 24,24% carbon, 4,04% hydrogen and 71,72% chlorine. From another experiment the molecular mass was found to be 99 g · mol - 1 . Deduce the empirical and molecular formula.

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Source:  OpenStax, Siyavula textbooks: grade 10 physical science [caps]. OpenStax CNX. Sep 30, 2011 Download for free at http://cnx.org/content/col11305/1.7
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