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A look back at and shows that the equilibrium pressure of the product of the reaction increases with increasingthe initial quantity of reaction. This seems quite intuitive. Less intuitive is the variation of the equilibrium pressure of theproduct of this reaction with variation in the volume of the container, as shown in . Note that the pressure of N H 3 decreases by more than a factor of ten when the volume is increased by a factor of ten. This means that, at equilibrium, there arefewer moles of N H 3 produced when the reaction occurs in a larger volume.

To understand this effect, we rewrite the equilibrium constant in to explicit show the volume of the container. This is done by applying Dalton's Law of Partial Pressures , so that each partial pressure is given by the Ideal Gas Law:

K p n N H 3 2 R T V 2 n N 2 R T V n H 2 3 R T V 3 n N H 3 2 n N 2 n H 2 3 R T V 2

Therefore,

K p R T V 2 n N H 3 2 n N 2 n H 2 3

This form of the equation makes it clear that, when the volume increases, the left side of the equation decreases.This means that the right side of the equation must decrease also, and in turn, n N H 3 must decrease while n N 2 and n H 2 must increase. The equilibrium is thus shifted from products toreactants when the volume increases for this reaction .

The effect of changing the volume must be considered for each specific reaction, because the effect dependson the stoichiometry of the reaction. One way to determine the consequence of a change in volume is to rewrite the equilibriumconstant as we have done in .

Finally, we consider changes in temperature. We note that K p increases with T for endothermic reactions and decreases with T for exothermic reactions. As such, the products are increasinglyfavored with increasing temperature when the reaction is endothermic, and the reactants are increasingly favored withincreasing temperature when the reaction is exothermic. On reflection, we note that when the reaction is exothermic, thereverse reaction is endothermic. Putting these statements together, we can say that the reaction equilibrium always shifts in thedirection of the endothermic reaction when the temperature is increased.

All of these observations can be collected into a single unifying concept known as Le Châtelier's Principle .

Le châtelier's principle

When a reaction at equilibrium is stressed by a change in conditions, the equilibrium will be reestablished insuch a way as to counter the stress.

This statement is best understood by reflection on the types of "stresses" we haveconsidered in this section. When a reactant is added to a system at equilibrium, the reaction responds by consuming some of that addedreactant as it establishes a new equilibrium. This offsets some of the stress of the increase in reactant. When the temperature israised for a reaction at equilibrium, this adds thermal energy. The system shifts the equilibrium in the endothermic direction, thusabsorbing some of the added thermal energy, countering the stress.

The most challenging of the three types of stress considered in this section is the change in volume. Byincreasing the volume containing a gas phase reaction at equilibrium, we reduce the partial pressures of all gases present and thus reduce the total pressure. Recall that the response of this reaction to the volume increase was to create more of the reactants at theexpense of the products. One consequence of this shift is that more gas molecules are created, and this increases the total pressure inthe reaction flask. Thus, the reaction responds to the stress of the volume increase by partially offsetting the pressure decreasewith an increase in the number of moles of gas at equilibrium.

Le Châtelier's principle is a useful mnemonic for predicting how we might increase or decreasethe amount of product at equilibrium by changing the conditions of the reaction. From this principle, we can predict whether thereaction should occur at high temperature or low temperature, and whether it should occur at high pressure or low pressure.

Review and discussion questions

In the data given for equilibrium of this reaction , there is no volume given. Show that changing the volume for the reactiondoes not change the number of moles of reactants and products present at equilibrium, i.e. changing the volume does not shift the equilibrium.

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For this reaction the number of moles of N O 2 at equilibrium increases if we increase the volume in which the reaction is contained. Explain why this must be true in terms ofdynamic equilibrium, give a reason why the rates of the forward and reverse reactions might be affected differently by changes in thevolume.

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We could balance by writing

2 N 2 ( g ) + 6 H 2 ( g ) 4 N H 3 ( g )

Write the form of the equilibrium constant for the reaction balanced as in . What is the value of the equilibrium constant? (Refer to .) Of course, the pressures at equilibrium do not depend on whether the reaction is balanced as in or as in . Explain why this is true, even though the equilibrium constant can be written differently and havea different value.

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Show that the equilibrium constant K p in for this reaction can be written in terms of the concentrations or particle densities, e.g. [ N 2 ] n N 2 V , instead of the partial pressures. In this form, we call theequilibrium constant K c . Find the relationship between K p and K c , and calculate the value of K c .

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For each of these reactions, predict whether increases in temperature will shift the reaction equilibrium moretowards products or more towards reactants.

2 C O ( g ) + O 2 ( g ) 2 C O 2 ( g )

O 3 ( g ) + N O ( g ) N O 2 ( g ) + O 2 ( g )

2 O 3 ( g ) 3 O 2 ( g )

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Plot the data in on a graph showing K p on the y-axis and T on the x-axis. The shape of this graph is reminiscent of the graph ofanother physical property as a function of increasing temperature. Identify that property, and suggest a reason why the shapes of thegraphs might be similar.

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Using Le Châtelier's principle, predict whether the specified "stress" will produce anincrease or a decrease in the amount of product observed at equilibrium for the reaction:

2 H 2 ( g ) + C O ( g ) C H 3 O H ( g )

Δ H ° -91 kJ mol

Volume of container is increased.

Helium is added to container.

Temperature of container is raised.

Hydrogen is added to container.

C H 3 O H is extracted from container as it is formed.

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Questions & Answers

Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Kate Reply
what is the change in momentum of a body?
Eunice Reply
what is a capacitor?
Raymond Reply
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
Maria Reply
please solve
Sharon
8m/s²
Aishat
What is Thermodynamics
Muordit
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
Saheed Reply
50 m/s due south east
Someone
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
Ramon Reply
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
Someone
definitely of physics
Haryormhidey Reply
how many start and codon
Esrael Reply
what is field
Felix Reply
physics, biology and chemistry this is my Field
ALIYU
field is a region of space under the influence of some physical properties
Collete
what is ogarnic chemistry
WISDOM Reply
determine the slope giving that 3y+ 2x-14=0
WISDOM
Another formula for Acceleration
Belty Reply
a=v/t. a=f/m a
IHUMA
innocent
Adah
pratica A on solution of hydro chloric acid,B is a solution containing 0.5000 mole ofsodium chlorid per dm³,put A in the burret and titrate 20.00 or 25.00cm³ portion of B using melting orange as the indicator. record the deside of your burret tabulate the burret reading and calculate the average volume of acid used?
Nassze Reply
how do lnternal energy measures
Esrael
Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
JALLAH Reply
No. According to Isac Newtons law. this two bodies maybe you and the wall beside you. Attracting depends on the mass och each body and distance between them.
Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Robert
like charges repel while unlike charges atttact
Raymond
What is specific heat capacity
Destiny Reply
Specific heat capacity is a measure of the amount of energy required to raise the temperature of a substance by one degree Celsius (or Kelvin). It is measured in Joules per kilogram per degree Celsius (J/kg°C).
AI-Robot
specific heat capacity is the amount of energy needed to raise the temperature of a substance by one degree Celsius or kelvin
ROKEEB
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Source:  OpenStax, General chemistry ii. OpenStax CNX. Mar 25, 2005 Download for free at http://cnx.org/content/col10262/1.2
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