<< Chapter < Page Chapter >> Page >

Show that the functions f ( x , y ) = 2 x 2 y 3 + 3 and g ( x , y ) = ( 2 x 2 y 3 + 3 ) 4 are continuous everywhere.

The polynomials g ( x ) = 2 x 2 and h ( y ) = y 3 are continuous at every real number; therefore, by the product of continuous functions theorem, f ( x , y ) = 2 x 2 y 3 is continuous at every point ( x , y ) in the x y -plane. Furthermore, any constant function is continuous everywhere, so g ( x , y ) = 3 is continuous at every point ( x , y ) in the x y -plane. Therefore, f ( x , y ) = 2 x 2 y 3 + 3 is continuous at every point ( x , y ) in the x y -plane. Last, h ( x ) = x 4 is continuous at every real number x , so by the continuity of composite functions theorem g ( x , y ) = ( 2 x 2 y 3 + 3 ) 4 is continuous at every point ( x , y ) in the x y -plane.

Got questions? Get instant answers now!

Functions of three or more variables

The limit of a function of three or more variables occurs readily in applications. For example, suppose we have a function f ( x , y , z ) that gives the temperature at a physical location ( x , y , z ) in three dimensions. Or perhaps a function g ( x , y , z , t ) can indicate air pressure at a location ( x , y , z ) at time t . How can we take a limit at a point in 3 ? What does it mean to be continuous at a point in four dimensions?

The answers to these questions rely on extending the concept of a δ disk into more than two dimensions. Then, the ideas of the limit of a function of three or more variables and the continuity of a function of three or more variables are very similar to the definitions given earlier for a function of two variables.

Definition

Let ( x 0 , y 0 , z 0 ) be a point in 3 . Then, a δ ball    in three dimensions consists of all points in 3 lying at a distance of less than δ from ( x 0 , y 0 , z 0 ) —that is,

{ ( x , y , z ) 3 | ( x x 0 ) 2 + ( y y 0 ) 2 + ( z z 0 ) 2 < δ } .

To define a δ ball in higher dimensions, add additional terms under the radical to correspond to each additional dimension. For example, given a point P = ( w 0 , x 0 , y 0 , z 0 ) in 4 , a δ ball around P can be described by

{ ( w , x , y , z ) 4 | ( w w 0 ) 2 + ( x x 0 ) 2 + ( y y 0 ) 2 + ( z z 0 ) 2 < δ } .

To show that a limit of a function of three variables exists at a point ( x 0 , y 0 , z 0 ) , it suffices to show that for any point in a δ ball centered at ( x 0 , y 0 , z 0 ) , the value of the function at that point is arbitrarily close to a fixed value (the limit value). All the limit laws for functions of two variables hold for functions of more than two variables as well.

Finding the limit of a function of three variables

Find lim ( x , y , z ) ( 4 , 1 , −3 ) x 2 y 3 z 2 x + 5 y z .

Before we can apply the quotient law, we need to verify that the limit of the denominator is nonzero. Using the difference law, the identity law, and the constant law,

lim ( x , y , z ) ( 4 , 1 , −3 ) ( 2 x + 5 y z ) = 2 ( lim ( x , y , z ) ( 4 , 1 , −3 ) x ) + 5 ( lim ( x , y , z ) ( 4 , 1 , −3 ) y ) ( lim ( x , y , z ) ( 4 , 1 , −3 ) z ) = 2 ( 4 ) + 5 ( 1 ) ( −3 ) = 16.

Since this is nonzero, we next find the limit of the numerator. Using the product law, difference law, constant multiple law, and identity law,

lim ( x , y , z ) ( 4 , 1 , −3 ) ( x 2 y 3 z ) = ( lim ( x , y , z ) ( 4 , 1 , −3 ) x ) 2 ( lim ( x , y , z ) ( 4 , 1 , −3 ) y ) 3 lim ( x , y , z ) ( 4 , 1 , −3 ) z = ( 4 2 ) ( 1 ) 3 ( −3 ) = 16 + 9 = 25 .

Last, applying the quotient law:

lim ( x , y , z ) ( 4 , 1 , −3 ) x 2 y 3 z 2 x + 5 y z = lim ( x , y , z ) ( 4 , 1 , −3 ) ( x 2 y 3 z ) lim ( x , y , z ) ( 4 , 1 , −3 ) ( 2 x + 5 y z ) = 25 16 .
Got questions? Get instant answers now!
Got questions? Get instant answers now!

Find lim ( x , y , z ) ( 4 , −1 , 3 ) 13 x 2 2 y 2 + z 2 .

lim ( x , y , z ) ( 4 , −1 , 3 ) 13 x 2 2 y 2 + z 2 = 2

Got questions? Get instant answers now!

Key concepts

  • To study limits and continuity for functions of two variables, we use a δ disk centered around a given point.
  • A function of several variables has a limit if for any point in a δ ball centered at a point P , the value of the function at that point is arbitrarily close to a fixed value (the limit value).
  • The limit laws established for a function of one variable have natural extensions to functions of more than one variable.
  • A function of two variables is continuous at a point if the limit exists at that point, the function exists at that point, and the limit and function are equal at that point.

Questions & Answers

I'm interested in biological psychology and cognitive psychology
Tanya Reply
what does preconceived mean
sammie Reply
physiological Psychology
Nwosu Reply
How can I develope my cognitive domain
Amanyire Reply
why is communication effective
Dakolo Reply
Communication is effective because it allows individuals to share ideas, thoughts, and information with others.
effective communication can lead to improved outcomes in various settings, including personal relationships, business environments, and educational settings. By communicating effectively, individuals can negotiate effectively, solve problems collaboratively, and work towards common goals.
it starts up serve and return practice/assessments.it helps find voice talking therapy also assessments through relaxed conversation.
miss
Every time someone flushes a toilet in the apartment building, the person begins to jumb back automatically after hearing the flush, before the water temperature changes. Identify the types of learning, if it is classical conditioning identify the NS, UCS, CS and CR. If it is operant conditioning, identify the type of consequence positive reinforcement, negative reinforcement or punishment
Wekolamo Reply
please i need answer
Wekolamo
because it helps many people around the world to understand how to interact with other people and understand them well, for example at work (job).
Manix Reply
Agreed 👍 There are many parts of our brains and behaviors, we really need to get to know. Blessings for everyone and happy Sunday!
ARC
A child is a member of community not society elucidate ?
JESSY Reply
Isn't practices worldwide, be it psychology, be it science. isn't much just a false belief of control over something the mind cannot truly comprehend?
Simon Reply
compare and contrast skinner's perspective on personality development on freud
namakula Reply
Skinner skipped the whole unconscious phenomenon and rather emphasized on classical conditioning
war
explain how nature and nurture affect the development and later the productivity of an individual.
Amesalu Reply
nature is an hereditary factor while nurture is an environmental factor which constitute an individual personality. so if an individual's parent has a deviant behavior and was also brought up in an deviant environment, observation of the behavior and the inborn trait we make the individual deviant.
Samuel
I am taking this course because I am hoping that I could somehow learn more about my chosen field of interest and due to the fact that being a PsyD really ignites my passion as an individual the more I hope to learn about developing and literally explore the complexity of my critical thinking skills
Zyryn Reply
good👍
Jonathan
and having a good philosophy of the world is like a sandwich and a peanut butter 👍
Jonathan
generally amnesi how long yrs memory loss
Kelu Reply
interpersonal relationships
Abdulfatai Reply
What would be the best educational aid(s) for gifted kids/savants?
Heidi Reply
treat them normal, if they want help then give them. that will make everyone happy
Saurabh
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply
Practice Key Terms 8

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Calculus volume 3' conversation and receive update notifications?

Ask