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Colors of complexes

The octahedral complex [Ti(H 2 O) 6 ] 3+ has a single d electron. To excite this electron from the ground state t 2 g orbital to the e g orbital, this complex absorbs light from 450 to 600 nm. The maximum absorbance corresponds to Δ oct and occurs at 499 nm. Calculate the value of Δ oct in Joules and predict what color the solution will appear.

Solution

Using Planck's equation (refer to the section on electromagnetic energy), we calculate:

v = c λ so 3.00 × 10 8 m/s 499 nm × 1 m 10 9 nm = 6.01 × 10 14 Hz
E = h n u so 6.63 × 10 −34 J · s × 6.01 × 10 14 Hz = 3.99 × 10 −19 Joules/ion

Because the complex absorbs 600 nm (orange) through 450 (blue), the indigo, violet, and red wavelengths will be transmitted, and the complex will appear purple.

Check your learning

A complex that appears green, absorbs photons of what wavelengths?

Answer:

red, 620–800 nm

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Small changes in the relative energies of the orbitals that electrons are transitioning between can lead to drastic shifts in the color of light absorbed. Therefore, the colors of coordination compounds depend on many factors. As shown in [link] , different aqueous metal ions can have different colors. In addition, different oxidation states of one metal can produce different colors, as shown for the vanadium complexes in the link below.

This figure shows three containers filled with liquids of different colors. The first appears to be purple, the second, orange, and the third red.
The partially filled d orbitals of the stable ions Cr 3+ ( aq ), Fe 3+ ( aq ), and Co 2+ ( aq ) (left, center and right, respectively) give rise to various colors. (credit: Sahar Atwa)

The specific ligands coordinated to the metal center also influence the color of coordination complexes. For example, the iron(II) complex [Fe(H 2 O) 6 ]SO 4 appears blue-green because the high-spin complex absorbs photons in the red wavelengths ( [link] ). In contrast, the low-spin iron(II) complex K 4 [Fe(CN) 6 ] appears pale yellow because it absorbs higher-energy violet photons.

Two photos are shown. Photo a on the left shows a small mound of a white crystalline powder with a very faint yellow tint on a watch glass. Photo b shows a small mound of a yellow-tan crystalline powder.
Both (a) hexaaquairon(II) sulfate and (b) potassium hexacyanoferrate(II) contain d 6 iron(II) octahedral metal centers, but they absorb photons in different ranges of the visible spectrum.

In general, strong-field ligands cause a large split in the energies of d orbitals of the central metal atom (large Δ oct ). Transition metal coordination compounds with these ligands are yellow, orange, or red because they absorb higher-energy violet or blue light. On the other hand, coordination compounds of transition metals with weak-field ligands are often blue-green, blue, or indigo because they absorb lower-energy yellow, orange, or red light.

A coordination compound of the Cu + ion has a d 10 configuration, and all the e g orbitals are filled. To excite an electron to a higher level, such as the 4 p orbital, photons of very high energy are necessary. This energy corresponds to very short wavelengths in the ultraviolet region of the spectrum. No visible light is absorbed, so the eye sees no change, and the compound appears white or colorless. A solution containing [Cu(CN) 2 ] , for example, is colorless. On the other hand, octahedral Cu 2+ complexes have a vacancy in the e g orbitals, and electrons can be excited to this level. The wavelength (energy) of the light absorbed corresponds to the visible part of the spectrum, and Cu 2+ complexes are almost always colored—blue, blue-green violet, or yellow ( [link] ). Although CFT successfully describes many properties of coordination complexes, molecular orbital explanations (beyond the introductory scope provided here) are required to understand fully the behavior of coordination complexes.

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Source:  OpenStax, Chemistry. OpenStax CNX. May 20, 2015 Download for free at http://legacy.cnx.org/content/col11760/1.9
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