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[link] shows the same curve divided into eight subintervals. Comparing the graph with four rectangles in [link] with this graph with eight rectangles, we can see there appears to be less white space under the curve when n = 8 . This white space is area under the curve we are unable to include using our approximation. The area of the rectangles is

L 8 = f ( 0 ) ( 0.25 ) + f ( 0.25 ) ( 0.25 ) + f ( 0.5 ) ( 0.25 ) + f ( 0.75 ) ( 0.25 ) + f ( 1 ) ( 0.25 ) + f ( 1.25 ) ( 0.25 ) + f ( 1.5 ) ( 0.25 ) + f ( 1.75 ) ( 0.25 ) = 7.75.
A graph showing the left-endpoint approximation for the area under the given curve from a=x0 to b = x8. The heights of the rectangles are determined by the values of the function at the left endpoints.
The region under the curve is divided into n = 8 rectangular areas of equal width for a left-endpoint approximation.

The graph in [link] shows the same function with 32 rectangles inscribed under the curve. There appears to be little white space left. The area occupied by the rectangles is

L 32 = f ( 0 ) ( 0.0625 ) + f ( 0.0625 ) ( 0.0625 ) + f ( 0.125 ) ( 0.0625 ) + + f ( 1.9375 ) ( 0.0625 ) = 7.9375.
A graph of the left-endpoint approximation of the area under the given curve from a = x0 to b = x32. The heights of the rectangles are determined by the values of the function at the left endpoints.
Here, 32 rectangles are inscribed under the curve for a left-endpoint approximation.

We can carry out a similar process for the right-endpoint approximation method. A right-endpoint approximation of the same curve, using four rectangles ( [link] ), yields an area

R 4 = f ( 0.5 ) ( 0.5 ) + f ( 1 ) ( 0.5 ) + f ( 1.5 ) ( 0.5 ) + f ( 2 ) ( 0.5 ) = 8.5.
A graph of the right-endpoint approximation for the area under the given curve from x0 to x4. The heights of the rectangles are determined by the values of the function at the right endpoints.
Now we divide the area under the curve into four equal subintervals for a right-endpoint approximation.

Dividing the region over the interval [ 0 , 2 ] into eight rectangles results in Δ x = 2 0 8 = 0.25 . The graph is shown in [link] . The area is

R 8 = f ( 0.25 ) ( 0.25 ) + f ( 0.5 ) ( 0.25 ) + f ( 0.75 ) ( 0.25 ) + f ( 1 ) ( 0.25 ) + f ( 1.25 ) ( 0.25 ) + f ( 1.5 ) ( 0.25 ) + f ( 1.75 ) ( 0.25 ) + f ( 2 ) ( 0.25 ) = 8.25.
A graph of the right-endpoint approximation for the area under the given curve from a=x0 to b=x8.The heights of the rectangles are determined by the values of the function at the right endpoints.
Here we use right-endpoint approximation for a region divided into eight equal subintervals.

Last, the right-endpoint approximation with n = 32 is close to the actual area ( [link] ). The area is approximately

R 32 = f ( 0.0625 ) ( 0.0625 ) + f ( 0.125 ) ( 0.0625 ) + f ( 0.1875 ) ( 0.0625 ) + + f ( 2 ) ( 0.0625 ) = 8.0625.
A graph of the right-endpoint approximation for the area under the given curve from a=x0 to b=x32. The heights of the rectangles are determined by the values of the function at the right endpoints.
The region is divided into 32 equal subintervals for a right-endpoint approximation.

Based on these figures and calculations, it appears we are on the right track; the rectangles appear to approximate the area under the curve better as n gets larger. Furthermore, as n increases, both the left-endpoint and right-endpoint approximations appear to approach an area of 8 square units. [link] shows a numerical comparison of the left- and right-endpoint methods. The idea that the approximations of the area under the curve get better and better as n gets larger and larger is very important, and we now explore this idea in more detail.

Converging values of left- and right-endpoint approximations as n Increases
Values of n Approximate Area L n Approximate Area R n
n = 4 7.5 8.5
n = 8 7.75 8.25
n = 32 7.94 8.06

Forming riemann sums

So far we have been using rectangles to approximate the area under a curve. The heights of these rectangles have been determined by evaluating the function at either the right or left endpoints of the subinterval [ x i 1 , x i ] . In reality, there is no reason to restrict evaluation of the function to one of these two points only. We could evaluate the function at any point c i in the subinterval [ x i 1 , x i ] , and use f ( x i * ) as the height of our rectangle. This gives us an estimate for the area of the form

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In economics, a perfect market refers to a theoretical construct where all participants have perfect information, goods are homogenous, there are no barriers to entry or exit, and prices are determined solely by supply and demand. It's an idealized model used for analysis,
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AI-Robot
When MP₁ becomes negative, TP start to decline. Extuples Suppose that the short-run production function of certain cut-flower firm is given by: Q=4KL-0.6K2 - 0.112 • Where is quantity of cut flower produced, I is labour input and K is fixed capital input (K-5). Determine the average product of lab
Kelo
Extuples Suppose that the short-run production function of certain cut-flower firm is given by: Q=4KL-0.6K2 - 0.112 • Where is quantity of cut flower produced, I is labour input and K is fixed capital input (K-5). Determine the average product of labour (APL) and marginal product of labour (MPL)
Kelo
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Quantity demanded refers to the specific amount of a good or service that consumers are willing and able to purchase at a give price and within a specific time period. Demand, on the other hand, is a broader concept that encompasses the entire relationship between price and quantity demanded
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Jabir
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Asui
it is a curve that we get after connecting the pareto optimal combinations of two consumers after their mutually beneficial trade offs
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In economics, the contract curve refers to the set of points in an Edgeworth box diagram where both parties involved in a trade cannot be made better off without making one of them worse off. It represents the Pareto efficient allocations of goods between two individuals or entities, where neither p
Cornelius
In economics, the contract curve refers to the set of points in an Edgeworth box diagram where both parties involved in a trade cannot be made better off without making one of them worse off. It represents the Pareto efficient allocations of goods between two individuals or entities,
Cornelius
Suppose a consumer consuming two commodities X and Y has The following utility function u=X0.4 Y0.6. If the price of the X and Y are 2 and 3 respectively and income Constraint is birr 50. A,Calculate quantities of x and y which maximize utility. B,Calculate value of Lagrange multiplier. C,Calculate quantities of X and Y consumed with a given price. D,alculate optimum level of output .
Feyisa Reply
Answer
Feyisa
c
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Source:  OpenStax, Calculus volume 1. OpenStax CNX. Feb 05, 2016 Download for free at http://cnx.org/content/col11964/1.2
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