5.7 Inverses and radical functions  (Page 5/7)

Explain why we cannot find inverse functions for all polynomial functions.

Why must we restrict the domain of a quadratic function when finding its inverse?

When finding the inverse of a radical function, what restriction will we need to make?

The inverse of a quadratic function will always take what form?

$f\left(x\right)={\left(x-4\right)}^2, [4,\infty )$

$f\left(x\right)={\left(x+2\right)}^2, [\mathrm{-2},\infty )$

$f(x)={\left(x+1\right)}^2-3, [\mathrm{-1},\infty )$

$f(x)=3x^2+5,\left(\infty ,0\right]$

$f\left(x\right)=12-x^2, [0,\infty )$

$f\left(x\right)=9-x^2, [0,\infty )$

$f(x)=2x^2+4, [0,\infty )$

$f(x)=x^3+5$

$f\left(x\right)=3x^3+1$

$f(x)=4-x^3$

$f\left(x\right)=4-2x^3$

$f(x)=\sqrt{2x+1}$

$f(x)=\sqrt{3-4x}$

$f\left(x\right)=9+\sqrt{4x-4}$