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q = m drop g E = m drop gd V , size 12{q= { {m rSub { size 8{"drop"} } g} over {E} } = { {m rSub { size 8{"drop"} } ital "gd"} over {V} } ,} {}

where d size 12{d} {} is the separation of the plates and V size 12{V} {} is the voltage that holds the drop motionless. (The same drop can be observed for several hours to see that it really is motionless.) By 1913 Millikan had measured the charge of the electron q e size 12{q rSub { size 8{e} } } {} to an accuracy of 1%, and he improved this by a factor of 10 within a few years to a value of 1 . 60 × 10 19 C size 12{ - 1 "." "60" times "10" rSup { size 8{ - "19"} } " C"} {} . He also observed that all charges were multiples of the basic electron charge and that sudden changes could occur in which electrons were added or removed from the drops. For this very fundamental direct measurement of q e size 12{q rSub { size 8{e} } } {} and for his studies of the photoelectric effect, Millikan was awarded the 1923 Nobel Prize in Physics.

With the charge of the electron known and the charge-to-mass ratio known, the electron’s mass can be calculated. It is

m = q e q e m e . size 12{m= { {q rSub { size 8{e} } } over { left ( { {q rSub { size 8{e} } } over {m rSub { size 8{e} } } } right )} } "." } {}

Substituting known values yields

m e = 1.60 × 10 19 C 1 . 76 × 10 11 C/kg size 12{m rSub { size 8{e} } = { { - 1 "." "60" times "10" rSup { size 8{ - "19"} } " C"} over { - 1 "." "76" times "10" rSup { size 8{"11"} } {C} slash {"kg"} } } } {}

or

m e = 9 . 11 × 10 31 kg (electron’s mass), size 12{m rSub { size 8{e} } =9 "." "11" times "10" rSup { size 8{ - "31"} } " kg"} {}

where the round-off errors have been corrected. The mass of the electron has been verified in many subsequent experiments and is now known to an accuracy of better than one part in one million. It is an incredibly small mass and remains the smallest known mass of any particle that has mass. (Some particles, such as photons, are massless and cannot be brought to rest, but travel at the speed of light.) A similar calculation gives the masses of other particles, including the proton. To three digits, the mass of the proton is now known to be

m p = 1 . 67 × 10 27 kg (proton’s mass), size 12{m rSub { size 8{P} } =1 "." "67" times "10" rSup { size 8{ - "27"} } " kg"} {}

which is nearly identical to the mass of a hydrogen atom. What Thomson and Millikan had done was to prove the existence of one substructure of atoms, the electron, and further to show that it had only a tiny fraction of the mass of an atom. The nucleus of an atom contains most of its mass, and the nature of the nucleus was completely unanticipated.

Another important characteristic of quantum mechanics was also beginning to emerge. All electrons are identical to one another. The charge and mass of electrons are not average values; rather, they are unique values that all electrons have. This is true of other fundamental entities at the submicroscopic level. All protons are identical to one another, and so on.

The nucleus

Here, we examine the first direct evidence of the size and mass of the nucleus. In later chapters, we will examine many other aspects of nuclear physics, but the basic information on nuclear size and mass is so important to understanding the atom that we consider it here.

Nuclear radioactivity was discovered in 1896, and it was soon the subject of intense study by a number of the best scientists in the world. Among them was New Zealander Lord Ernest Rutherford, who made numerous fundamental discoveries and earned the title of “father of nuclear physics.” Born in Nelson, Rutherford did his postgraduate studies at the Cavendish Laboratories in England before taking up a position at McGill University in Canada where he did the work that earned him a Nobel Prize in Chemistry in 1908. In the area of atomic and nuclear physics, there is much overlap between chemistry and physics, with physics providing the fundamental enabling theories. He returned to England in later years and had six future Nobel Prize winners as students. Rutherford used nuclear radiation to directly examine the size and mass of the atomic nucleus. The experiment he devised is shown in [link] . A radioactive source that emits alpha radiation was placed in a lead container with a hole in one side to produce a beam of alpha particles, which are a type of ionizing radiation ejected by the nuclei of a radioactive source. A thin gold foil was placed in the beam, and the scattering of the alpha particles was observed by the glow they caused when they struck a phosphor screen.

Questions & Answers

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what's Thermochemistry
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the study of the heat energy which is associated with chemical reactions
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Read Chapter 6, section 5
Dr
Read Chapter 6, section 5
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atomic radius is the distance between the nucleus of an atom and its valence shell
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Read Chapter 6, section 5
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It has no oxygen then
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read the chapter on thermochemistry...the sections on "PV" work and the First Law of Thermodynamics should help..
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definition of the periodic table
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Source:  OpenStax, College physics for ap® courses. OpenStax CNX. Nov 04, 2016 Download for free at https://legacy.cnx.org/content/col11844/1.14
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