<< Chapter < Page Chapter >> Page >
  • Define diffusion, osmosis, dialysis, and active transport.
  • Calculate diffusion rates.

Diffusion

There is something fishy about the ice cube from your freezer—how did it pick up those food odors? How does soaking a sprained ankle in Epsom salt reduce swelling? The answer to these questions are related to atomic and molecular transport phenomena—another mode of fluid motion. Atoms and molecules are in constant motion at any temperature. In fluids they move about randomly even in the absence of macroscopic flow. This motion is called a random walk and is illustrated in [link] . Diffusion is the movement of substances due to random thermal molecular motion. Fluids, like fish fumes or odors entering ice cubes, can even diffuse through solids.

Diffusion is a slow process over macroscopic distances. The densities of common materials are great enough that molecules cannot travel very far before having a collision that can scatter them in any direction, including straight backward. It can be shown that the average distance x rms size 12{x rSub { size 8{"rms"} } } {} that a molecule travels is proportional to the square root of time:

x rms = 2 Dt , size 12{x rSub { size 8{"rms"} } = sqrt {2 ital "Dt"} } {}

where x rms stands for the root-mean-square distance and is the statistical average for the process. The quantity D size 12{D} {} is the diffusion constant for the particular molecule in a specific medium. [link] lists representative values of D size 12{D} {} for various substances, in units of m 2 /s size 12{m rSup { size 8{2} } "/s"} {} .

The figure shows the path of a random walk. The random thermal motion of a molecule is shown to begin at a start point and then the particles move about zigzag in all directions and end up at the finish point. The distance between the start and finish point is shown as x. Continuous arrows show various directions of motion.
The random thermal motion of a molecule in a fluid in time t size 12{t} {} . This type of motion is called a random walk.
Diffusion constants for various molecules At 20°C and 1 atm
Diffusing molecule Medium D (m 2 /s)
Hydrogen ( H 2 ) Air 6.4 × 10 –5
Oxygen ( O 2 ) Air 1.8 × 10 –5
Oxygen ( O 2 ) Water 1.0 × 10 –9
Glucose ( C 6 H 12 O 6 ) Water 6.7 × 10 –10
Hemoglobin Water 6.9 × 10 –11
DNA Water 1.3 × 10 –12

Note that D size 12{D} {} gets progressively smaller for more massive molecules. This decrease is because the average molecular speed at a given temperature is inversely proportional to molecular mass. Thus the more massive molecules diffuse more slowly. Another interesting point is that D size 12{D} {} for oxygen in air is much greater than D size 12{D} {} for oxygen in water. In water, an oxygen molecule makes many more collisions in its random walk and is slowed considerably. In water, an oxygen molecule moves only about 40 μ m in 1 s. (Each molecule actually collides about 10 10 size 12{"10" rSup { size 8{"10"} } } {} times per second!). Finally, note that diffusion constants increase with temperature, because average molecular speed increases with temperature. This is because the average kinetic energy of molecules, 1 2 mv 2 size 12{ { { size 8{1} } over { size 8{2} } } ital "mv" rSup { size 8{2} } } {} , is proportional to absolute temperature.

Calculating diffusion: how long does glucose diffusion take?

Calculate the average time it takes a glucose molecule to move 1.0 cm in water.

Strategy

We can use x rms = 2 D t size 12{x rSub { size 8{"rms"} } = sqrt {2 ital "Dt"} } {} , the expression for the average distance moved in time t size 12{t} {} , and solve it for t size 12{t} {} . All other quantities are known.

Solution

Solving for t size 12{t} {} and substituting known values yields

t = x rms 2 2 D = ( 0.010 m ) 2 2 ( 6 . 7 × 10 10 m 2 /s ) = 7 . 5 × 10 4 s = 21 h .

Discussion

This is a remarkably long time for glucose to move a mere centimeter! For this reason, we stir sugar into water rather than waiting for it to diffuse.

Got questions? Get instant answers now!

Questions & Answers

find the equation of the tangent to the curve y=2x³-x²+3x+1 at the points x=1 and x=3
Esther Reply
derivative of logarithms function
Iqra Reply
how to solve this question
sidra
ex 2.1 question no 11
khansa
anyone can help me
khansa
question please
Rasul
ex 2.1 question no. 11
khansa
i cant type here
khansa
Find the derivative of g(x)=−3.
Abdullah Reply
any genius online ? I need help!!
Guzorochi Reply
how can i help you?
Pina
need to learn polynomial
Zakariya
i will teach...
nandu
I'm waiting
Zakariya
plz help me in question
Abish
How can I help you?
Tlou
evaluate the following computation (x³-8/x-2)
Murtala Reply
teach me how to solve the first law of calculus.
Uncle Reply
teach me also how to solve the first law of calculus
Bilson
what is differentiation
Ibrahim Reply
only god knows😂
abdulkadir
f(x) = x-2 g(x) = 3x + 5 fog(x)? f(x)/g(x)
Naufal Reply
fog(x)= f(g(x)) = x-2 = 3x+5-2 = 3x+3 f(x)/g(x)= x-2/3x+5
diron
pweding paturo nsa calculus?
jimmy
how to use fundamental theorem to solve exponential
JULIA Reply
find the bounded area of the parabola y^2=4x and y=16x
Omar Reply
what is absolute value means?
Geo Reply
Chicken nuggets
Hugh
🐔
MM
🐔🦃 nuggets
MM
(mathematics) For a complex number a+bi, the principal square root of the sum of the squares of its real and imaginary parts, √a2+b2 . Denoted by | |. The absolute value |x| of a real number x is √x2 , which is equal to x if x is non-negative, and −x if x is negative.
Ismael
find integration of loge x
Game Reply
find the volume of a solid about the y-axis, x=0, x=1, y=0, y=7+x^3
Godwin Reply
how does this work
Brad Reply
Can calculus give the answers as same as other methods give in basic classes while solving the numericals?
Cosmos Reply
log tan (x/4+x/2)
Rohan
please answer
Rohan
y=(x^2 + 3x).(eipix)
Claudia
is this a answer
Ismael
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply
Practice Key Terms 9

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, College physics. OpenStax CNX. Jul 27, 2015 Download for free at http://legacy.cnx.org/content/col11406/1.9
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'College physics' conversation and receive update notifications?

Ask